To read in two numbers x and n and then compute the sum of this geometric progression 1+x+x2+x3+……….+xn

Description:

In this program we have to read the two numbers and the calculate the sum of this geometric progression in above mention .

Algorithm:

Step 1: Start

Step 2: read values of x and n, sum-1, i=1

Step 3: check for n & X

i)                    if n<=0 || x<=0

ii)                  print values are not valid

iii)                read values of x and n

Step 4: perform the loop operation

i)                    for(i=1;i<=n;i++) then follows

ii)                  sum=sum+pow(x,i)

Step 5: print sum

Step 6: Stop

 Program:

#include<stdio.h>

#include<conio.h>

#include<math.h>

void main()

{

int s_sum,i,x,n;

clrscr();

printf("Enter the values for x and n:");

scanf("%d %d",&x,&n);

if(n<=0 || x<=0)

{

  printf("Value is not valid\n");

}

else

{

  printf("Value is valid\n");

  s_sum=1;

  for(i=1;i<=n;i++)

                         {

                         s_sum=s_sum+pow(x,i);

  }

                         printf("Sum of series=%d\n",s_sum);

}

getch();

}

Output:

1.Enter the values for x and n:2

   3

   Value is valid

    Sum of series=15

2.Enter the values for x and n:4

    9

    Value is valid

    Sum of series=21845

3.Enter the values for x and n:0

   1

   Value is not valid

Conclusion: the program is error free

VIVA QUESATIONS:

1) what are the difference between structures and unions ?

Ans: Here the major difference is  with in the structure all elements must be allocated memory. But in union highest memory allocation must be allocated the all these elements.